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101201120212020 = 223547535059133843
BaseRepresentation
bin10111000000101010111000…
…110100100011010000110100
3111021022201210001220022021020
4113000222320310203100310
5101231034343233241040
6555123053001221140
730213353046402453
oct2700527064432064
9437281701808236
10101201120212020
112a278177063124
12b4255564917b0
1344612bc83a3aa
141adc23601ab9a
15ba77179d4cd0
hex5c0ab8d23434

101201120212020 has 192 divisors, whose sum is σ = 294912854691840. Its totient is φ = 25909104379392.

The previous prime is 101201120211979. The next prime is 101201120212061. The reversal of 101201120212020 is 20212021102101.

It is an interprime number because it is at equal distance from previous prime (101201120211979) and next prime (101201120212061).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 756051219 + ... + 756185061.

It is an arithmetic number, because the mean of its divisors is an integer number (1536004451520).

Almost surely, 2101201120212020 is an apocalyptic number.

101201120212020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101201120212020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147456427345920).

101201120212020 is an abundant number, since it is smaller than the sum of its proper divisors (193711734479820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101201120212020 is a wasteful number, since it uses less digits than its factorization.

101201120212020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139014 (or 139012 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 101201120212020 its reverse (20212021102101), we get a palindrome (121413141314121).

The spelling of 101201120212020 in words is "one hundred one trillion, two hundred one billion, one hundred twenty million, two hundred twelve thousand, twenty".