101201120213 has 2 divisors, whose sum is σ = 101201120214. Its totient is φ = 101201120212.

The previous prime is 101201120197. The next prime is 101201120243. The reversal of 101201120213 is 312021102101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100966969009 + 234151204 = 317753^2 + 15302^2 .

It is an emirp because it is prime and its reverse (312021102101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101201120213 - 2⁴ = 101201120197 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101201120243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600560106 + 50600560107.

It is an arithmetic number, because the mean of its divisors is an integer number (50600560107).

Almost surely, 2^101201120213 is an apocalyptic number.

It is an amenable number.

101201120213 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201120213 is an equidigital number, since it uses as much as digits as its factorization.

101201120213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 101201120213 its reverse (312021102101), we get a palindrome (413222222314).

The spelling of 101201120213 in words is "one hundred one billion, two hundred one million, one hundred twenty thousand, two hundred thirteen".