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101201120197 is a prime number
BaseRepresentation
bin101111001000000001…
…1101000101111000101
3100200012212202120101221
41132100003220233011
53124224441321242
6114254031120341
710211600220442
oct1362003505705
9320185676357
10101201120197
1139a12437521
12177440730b1
13970a606a58
144c807a29c9
1529748e7167
hex17900e8bc5

101201120197 has 2 divisors, whose sum is σ = 101201120198. Its totient is φ = 101201120196.

The previous prime is 101201120161. The next prime is 101201120213. The reversal of 101201120197 is 791021102101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100667232961 + 533887236 = 317281^2 + 23106^2 .

It is a cyclic number.

It is not a de Polignac number, because 101201120197 - 211 = 101201118149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101201120107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600560098 + 50600560099.

It is an arithmetic number, because the mean of its divisors is an integer number (50600560099).

Almost surely, 2101201120197 is an apocalyptic number.

It is an amenable number.

101201120197 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201120197 is an equidigital number, since it uses as much as digits as its factorization.

101201120197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 25.

Adding to 101201120197 its reverse (791021102101), we get a palindrome (892222222298).

The spelling of 101201120197 in words is "one hundred one billion, two hundred one million, one hundred twenty thousand, one hundred ninety-seven".