101201207 has 2 divisors, whose sum is σ = 101201208. Its totient is φ = 101201206.

The previous prime is 101201197. The next prime is 101201209. The reversal of 101201207 is 702102101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101201207 - 2⁸ = 101200951 is a prime.

Together with 101201209, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101201191 and 101201200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101201209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600603 + 50600604.

It is an arithmetic number, because the mean of its divisors is an integer number (50600604).

Almost surely, 2^101201207 is an apocalyptic number.

101201207 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201207 is an equidigital number, since it uses as much as digits as its factorization.

101201207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 101201207 is about 10059.8810629152. The cubic root of 101201207 is about 466.0099941369.

Adding to 101201207 its reverse (702102101), we get a palindrome (803303308).

The spelling of 101201207 in words is "one hundred one million, two hundred one thousand, two hundred seven".