Base | Representation |
---|---|
bin | 11101011101000001001… |
… | …11110101010011110101 |
3 | 10120202011212022220010111 |
4 | 32232200213311103311 |
5 | 113040100100023333 |
6 | 2052524551423021 |
7 | 133054414004044 |
oct | 16564047652365 |
9 | 3522155286114 |
10 | 1012012111093 |
11 | 3602124a9835 |
12 | 144174984a71 |
13 | 74580ab0a99 |
14 | 36da58d855b |
15 | 1b4d10ca4cd |
hex | eba09f54f5 |
1012012111093 has 2 divisors, whose sum is σ = 1012012111094. Its totient is φ = 1012012111092.
The previous prime is 1012012111081. The next prime is 1012012111127. The reversal of 1012012111093 is 3901112102101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 622145492644 + 389866618449 = 788762^2 + 624393^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012012111093 - 213 = 1012012102901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012012111993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006055546 + 506006055547.
It is an arithmetic number, because the mean of its divisors is an integer number (506006055547).
Almost surely, 21012012111093 is an apocalyptic number.
It is an amenable number.
1012012111093 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012012111093 is an equidigital number, since it uses as much as digits as its factorization.
1012012111093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 22.
Adding to 1012012111093 its reverse (3901112102101), we get a palindrome (4913124213194).
The spelling of 1012012111093 in words is "one trillion, twelve billion, twelve million, one hundred eleven thousand, ninety-three".
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