Base | Representation |
---|---|
bin | 10111000000101010111110… |
… | …111101000010011101010111 |
3 | 111021022202001020111120101022 |
4 | 113000222332331002131113 |
5 | 101231040101103201442 |
6 | 555123111114351355 |
7 | 30213355436054234 |
oct | 2700527675023527 |
9 | 437282036446338 |
10 | 101201223100247 |
11 | 2a27821a147616 |
12 | b425584a2b55b |
13 | 4461307c526ba |
14 | 1adc24596078b |
15 | ba7721a5a3d2 |
hex | 5c0abef42757 |
101201223100247 has 2 divisors, whose sum is σ = 101201223100248. Its totient is φ = 101201223100246.
The previous prime is 101201223100183. The next prime is 101201223100297. The reversal of 101201223100247 is 742001322102101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101201223100247 - 26 = 101201223100183 is a prime.
It is a super-2 number, since 2×1012012231002472 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101201223100297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600611550123 + 50600611550124.
It is an arithmetic number, because the mean of its divisors is an integer number (50600611550124).
Almost surely, 2101201223100247 is an apocalyptic number.
101201223100247 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201223100247 is an equidigital number, since it uses as much as digits as its factorization.
101201223100247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 101201223100247 its reverse (742001322102101), we get a palindrome (843202545202348).
The spelling of 101201223100247 in words is "one hundred one trillion, two hundred one billion, two hundred twenty-three million, one hundred thousand, two hundred forty-seven".
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