1012013213003 has 4 divisors (see below), whose sum is σ = 1089860383248. Its totient is φ = 934166042760.

The previous prime is 1012013212993. The next prime is 1012013213009. The reversal of 1012013213003 is 3003123102101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1012013213003 - 2¹⁴ = 1012013196619 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1012013213009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38923585103 + ... + 38923585128.

It is an arithmetic number, because the mean of its divisors is an integer number (272465095812).

Almost surely, 2^{1012013213003} is an apocalyptic number.

1012013213003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1012013213003 is a deficient number, since it is larger than the sum of its proper divisors (77847170245).

1012013213003 is an equidigital number, since it uses as much as digits as its factorization.

1012013213003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77847170244.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1012013213003 its reverse (3003123102101), we get a palindrome (4015136315104).

The spelling of 1012013213003 in words is "one trillion, twelve billion, thirteen million, two hundred thirteen thousand, three".