101201411 has 2 divisors, whose sum is σ = 101201412. Its totient is φ = 101201410.

The previous prime is 101201389. The next prime is 101201417. The reversal of 101201411 is 114102101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101201411 - 2²⁶ = 34092547 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101201392 and 101201401.

It is not a weakly prime, because it can be changed into another prime (101201417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600705 + 50600706.

It is an arithmetic number, because the mean of its divisors is an integer number (50600706).

Almost surely, 2^101201411 is an apocalyptic number.

101201411 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201411 is an equidigital number, since it uses as much as digits as its factorization.

101201411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

The square root of 101201411 is about 10059.8912021950. The cubic root of 101201411 is about 466.0103072622.

Adding to 101201411 its reverse (114102101), we get a palindrome (215303512).

The spelling of 101201411 in words is "one hundred one million, two hundred one thousand, four hundred eleven".