10120211100017 has 2 divisors, whose sum is σ = 10120211100018. Its totient is φ = 10120211100016.

The previous prime is 10120211099963. The next prime is 10120211100019. The reversal of 10120211100017 is 71000111202101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9995234002576 + 124977097441 = 3161524^2 + 353521^2 .

It is an emirp because it is prime and its reverse (71000111202101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10120211100017 is a prime.

Together with 10120211100019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120211099968 and 10120211100004.

It is not a weakly prime, because it can be changed into another prime (10120211100019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060105550008 + 5060105550009.

It is an arithmetic number, because the mean of its divisors is an integer number (5060105550009).

Almost surely, 2^{10120211100017} is an apocalyptic number.

It is an amenable number.

10120211100017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120211100017 is an equidigital number, since it uses as much as digits as its factorization.

10120211100017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 10120211100017 its reverse (71000111202101), we get a palindrome (81120322302118).

The spelling of 10120211100017 in words is "ten trillion, one hundred twenty billion, two hundred eleven million, one hundred thousand, seventeen".