Base | Representation |
---|---|
bin | 10010110110011011… |
… | …00101111010101111 |
3 | 222010021222200001002 |
4 | 21123031211322233 |
5 | 131211234140211 |
6 | 4352115310515 |
7 | 505534326332 |
oct | 113315457257 |
9 | 28107880032 |
10 | 10120224431 |
11 | 432366a449 |
12 | 1b652ab43b |
13 | c538925a5 |
14 | 6c00da619 |
15 | 3e370a03b |
hex | 25b365eaf |
10120224431 has 4 divisors (see below), whose sum is σ = 10120433232. Its totient is φ = 10120015632.
The previous prime is 10120224409. The next prime is 10120224449. The reversal of 10120224431 is 13442202101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13442202101 = 401 ⋅33521701.
It is a cyclic number.
It is not a de Polignac number, because 10120224431 - 218 = 10119962287 is a prime.
It is a super-2 number, since 2×101202244312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10120224461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10331 + ... + 142643.
It is an arithmetic number, because the mean of its divisors is an integer number (2530108308).
Almost surely, 210120224431 is an apocalyptic number.
10120224431 is a deficient number, since it is larger than the sum of its proper divisors (208801).
10120224431 is an equidigital number, since it uses as much as digits as its factorization.
10120224431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 208800.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 10120224431 its reverse (13442202101), we get a palindrome (23562426532).
The spelling of 10120224431 in words is "ten billion, one hundred twenty million, two hundred twenty-four thousand, four hundred thirty-one".
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