Base | Representation |
---|---|
bin | 1001001101000101111000… |
… | …1000000110100001100011 |
3 | 1022211111211120212220011120 |
4 | 2103101132020012201203 |
5 | 2311303312131202210 |
6 | 33305145332343323 |
7 | 2063116654511163 |
oct | 223213610064143 |
9 | 38744746786146 |
10 | 10120522131555 |
11 | 32520a89a1320 |
12 | 1175512474b43 |
13 | 585490576374 |
14 | 26db9b94c5a3 |
15 | 1283d0b84270 |
hex | 9345e206863 |
10120522131555 has 128 divisors (see below), whose sum is σ = 18114307706880. Its totient is φ = 4784011200000.
The previous prime is 10120522131493. The next prime is 10120522131563. The reversal of 10120522131555 is 55513122502101.
It is not a de Polignac number, because 10120522131555 - 27 = 10120522131427 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 374668000 + ... + 374695010.
It is an arithmetic number, because the mean of its divisors is an integer number (141518028960).
Almost surely, 210120522131555 is an apocalyptic number.
10120522131555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10120522131555 is a deficient number, since it is larger than the sum of its proper divisors (7993785575325).
10120522131555 is a wasteful number, since it uses less digits than its factorization.
10120522131555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27473.
The product of its (nonzero) digits is 15000, while the sum is 33.
Adding to 10120522131555 its reverse (55513122502101), we get a palindrome (65633644633656).
The spelling of 10120522131555 in words is "ten trillion, one hundred twenty billion, five hundred twenty-two million, one hundred thirty-one thousand, five hundred fifty-five".
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