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10121323212113 is a prime number
BaseRepresentation
bin1001001101001000110111…
…0111111110110101010001
31022211120220102021000002212
42103102031313332311101
52311311432220241423
633305401030321505
72063145552545051
oct223221567766521
938746812230085
1010121323212113
11325247a0aaa73
1211756b67b9295
1358558a517029
1426dc360b9561
1512842b171578
hex9348ddfed51

10121323212113 has 2 divisors, whose sum is σ = 10121323212114. Its totient is φ = 10121323212112.

The previous prime is 10121323212059. The next prime is 10121323212131. The reversal of 10121323212113 is 31121232312101.

It is a happy number.

Together with next prime (10121323212131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6905369629249 + 3215953582864 = 2627807^2 + 1793308^2 .

It is a cyclic number.

It is not a de Polignac number, because 10121323212113 - 210 = 10121323211089 is a prime.

It is not a weakly prime, because it can be changed into another prime (10121323217113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060661606056 + 5060661606057.

It is an arithmetic number, because the mean of its divisors is an integer number (5060661606057).

Almost surely, 210121323212113 is an apocalyptic number.

It is an amenable number.

10121323212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10121323212113 is an equidigital number, since it uses as much as digits as its factorization.

10121323212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 10121323212113 its reverse (31121232312101), we get a palindrome (41242555524214).

The spelling of 10121323212113 in words is "ten trillion, one hundred twenty-one billion, three hundred twenty-three million, two hundred twelve thousand, one hundred thirteen".