Base | Representation |
---|---|
bin | 10010110110101001… |
… | …00001111110100101 |
3 | 222010102102002001122 |
4 | 21123110201332211 |
5 | 131212220341201 |
6 | 4352222303325 |
7 | 505555643216 |
oct | 113324417645 |
9 | 28112362048 |
10 | 10122043301 |
11 | 43246a1a47 |
12 | 1b65a27b45 |
13 | c5407b446 |
14 | 6c045140d |
15 | 3e3968e1b |
hex | 25b521fa5 |
10122043301 has 2 divisors, whose sum is σ = 10122043302. Its totient is φ = 10122043300.
The previous prime is 10122043277. The next prime is 10122043331. The reversal of 10122043301 is 10334022101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5278022500 + 4844020801 = 72650^2 + 69599^2 .
It is a cyclic number.
It is not a de Polignac number, because 10122043301 - 210 = 10122042277 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10122043301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10122043331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061021650 + 5061021651.
It is an arithmetic number, because the mean of its divisors is an integer number (5061021651).
Almost surely, 210122043301 is an apocalyptic number.
It is an amenable number.
10122043301 is a deficient number, since it is larger than the sum of its proper divisors (1).
10122043301 is an equidigital number, since it uses as much as digits as its factorization.
10122043301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 10122043301 its reverse (10334022101), we get a palindrome (20456065402).
The spelling of 10122043301 in words is "ten billion, one hundred twenty-two million, forty-three thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •