Base | Representation |
---|---|
bin | 11101011101011010001… |
… | …01000100000100011001 |
3 | 10120202201102120122102222 |
4 | 32232231011010010121 |
5 | 113041012100202223 |
6 | 2053001415033425 |
7 | 133062532251053 |
oct | 16565505040431 |
9 | 3522642518388 |
10 | 1012221100313 |
11 | 36030a4714a5 |
12 | 14421296b875 |
13 | 745b5194847 |
14 | 36dc557a8d3 |
15 | 1b4e460d0c8 |
hex | ebad144119 |
1012221100313 has 2 divisors, whose sum is σ = 1012221100314. Its totient is φ = 1012221100312.
The previous prime is 1012221100309. The next prime is 1012221100343. The reversal of 1012221100313 is 3130011222101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 984308047129 + 27913053184 = 992123^2 + 167072^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012221100313 - 22 = 1012221100309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1012221100291 and 1012221100300.
It is not a weakly prime, because it can be changed into another prime (1012221100343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506110550156 + 506110550157.
It is an arithmetic number, because the mean of its divisors is an integer number (506110550157).
Almost surely, 21012221100313 is an apocalyptic number.
It is an amenable number.
1012221100313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012221100313 is an equidigital number, since it uses as much as digits as its factorization.
1012221100313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1012221100313 its reverse (3130011222101), we get a palindrome (4142232322414).
The spelling of 1012221100313 in words is "one trillion, twelve billion, two hundred twenty-one million, one hundred thousand, three hundred thirteen".
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