101222113121 has 4 divisors (see below), whose sum is σ = 101302513200. Its totient is φ = 101141713044.

The previous prime is 101222113079. The next prime is 101222113127. The reversal of 101222113121 is 121311222101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101222113121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101222113121.

It is not an unprimeable number, because it can be changed into a prime (101222113127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40198151 + ... + 40200668.

It is an arithmetic number, because the mean of its divisors is an integer number (25325628300).

Almost surely, 2^101222113121 is an apocalyptic number.

It is an amenable number.

101222113121 is a deficient number, since it is larger than the sum of its proper divisors (80400079).

101222113121 is an equidigital number, since it uses as much as digits as its factorization.

101222113121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80400078.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101222113121 its reverse (121311222101), we get a palindrome (222533335222).

The spelling of 101222113121 in words is "one hundred one billion, two hundred twenty-two million, one hundred thirteen thousand, one hundred twenty-one".