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101222130001 = 823112297671
BaseRepresentation
bin101111001000101001…
…1110010000101010001
3100200021100021222102211
41132101103302011101
53124300331130001
6114300101312121
710212243623506
oct1362123620521
9320240258384
10101222130001
1139a232874a3
121774b105641
139711a819a5
144c834b14ad
152976697351
hex17914f2151

101222130001 has 4 divisors (see below), whose sum is σ = 101234435904. Its totient is φ = 101209824100.

The previous prime is 101222129951. The next prime is 101222130011. The reversal of 101222130001 is 100031222101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101222130001 - 211 = 101222127953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101222130011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6140605 + ... + 6157066.

It is an arithmetic number, because the mean of its divisors is an integer number (25308608976).

Almost surely, 2101222130001 is an apocalyptic number.

It is an amenable number.

101222130001 is a deficient number, since it is larger than the sum of its proper divisors (12305903).

101222130001 is an equidigital number, since it uses as much as digits as its factorization.

101222130001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12305902.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 101222130001 its reverse (100031222101), we get a palindrome (201253352102).

The spelling of 101222130001 in words is "one hundred one billion, two hundred twenty-two million, one hundred thirty thousand, one".

Divisors: 1 8231 12297671 101222130001