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101222131200 = 293526179547
BaseRepresentation
bin101111001000101001…
…1110010011000000000
3100200021100022001002020
41132101103302120000
53124300331144300
6114300101321440
710212243630141
oct1362123623000
9320240261066
10101222131200
1139a23288393
121774b106280
139711a823b8
144c834b1ac8
1529766978a0
hex17914f2600

101222131200 has 480 divisors, whose sum is σ = 344793884160. Its totient is φ = 26166067200.

The previous prime is 101222131183. The next prime is 101222131207. The reversal of 101222131200 is 2131222101.

It is a tau number, because it is divible by the number of its divisors (480).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 101222131200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101222131207) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 185049327 + ... + 185049873.

It is an arithmetic number, because the mean of its divisors is an integer number (718320592).

Almost surely, 2101222131200 is an apocalyptic number.

101222131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101222131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172396942080).

101222131200 is an abundant number, since it is smaller than the sum of its proper divisors (243571752960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101222131200 is an equidigital number, since it uses as much as digits as its factorization.

101222131200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 718 (or 697 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 101222131200 its reverse (2131222101), we get a palindrome (103353353301).

Subtracting from 101222131200 its reverse (2131222101), we obtain a palindrome (99090909099).

The spelling of 101222131200 in words is "one hundred one billion, two hundred twenty-two million, one hundred thirty-one thousand, two hundred".