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101232132223127 is a prime number
BaseRepresentation
bin10111000001000111110001…
…010001111111000010010111
3111021102200211100110200220012
4113001013301101333002113
5101232041401322120002
6555145222144230435
730215531415216143
oct2701076121770227
9437380740420805
10101232132223127
112a28a340584074
12b42b57030b41b
1344641c2786719
141add938a1c223
15ba84303b3d52
hex5c11f147f097

101232132223127 has 2 divisors, whose sum is σ = 101232132223128. Its totient is φ = 101232132223126.

The previous prime is 101232132223121. The next prime is 101232132223133. The reversal of 101232132223127 is 721322231232101.

It is a balanced prime because it is at equal distance from previous prime (101232132223121) and next prime (101232132223133).

It is a cyclic number.

It is not a de Polignac number, because 101232132223127 - 210 = 101232132222103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101232132223093 and 101232132223102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101232132223121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50616066111563 + 50616066111564.

It is an arithmetic number, because the mean of its divisors is an integer number (50616066111564).

Almost surely, 2101232132223127 is an apocalyptic number.

101232132223127 is a deficient number, since it is larger than the sum of its proper divisors (1).

101232132223127 is an equidigital number, since it uses as much as digits as its factorization.

101232132223127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 101232132223127 its reverse (721322231232101), we get a palindrome (822554363455228).

The spelling of 101232132223127 in words is "one hundred one trillion, two hundred thirty-two billion, one hundred thirty-two million, two hundred twenty-three thousand, one hundred twenty-seven".