10123221113 has 4 divisors (see below), whose sum is σ = 10185326928. Its totient is φ = 10061115300.

The previous prime is 10123221091. The next prime is 10123221167. The reversal of 10123221113 is 31112232101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31112232101 = 30133 ⋅1032497.

It is a cyclic number.

It is not a de Polignac number, because 10123221113 - 2¹² = 10123217017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10123221091 and 10123221100.

It is not an unprimeable number, because it can be changed into a prime (10123221193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31052663 + ... + 31052988.

It is an arithmetic number, because the mean of its divisors is an integer number (2546331732).

Almost surely, 2^10123221113 is an apocalyptic number.

It is an amenable number.

10123221113 is a deficient number, since it is larger than the sum of its proper divisors (62105815).

10123221113 is an equidigital number, since it uses as much as digits as its factorization.

10123221113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62105814.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10123221113 its reverse (31112232101), we get a palindrome (41235453214).

The spelling of 10123221113 in words is "ten billion, one hundred twenty-three million, two hundred twenty-one thousand, one hundred thirteen".