1012431113 has 4 divisors (see below), whose sum is σ = 1015625220. Its totient is φ = 1009237008.

The previous prime is 1012431109. The next prime is 1012431137. The reversal of 1012431113 is 3111342101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3111342101 = 7 ⋅444477443.

It can be written as a sum of positive squares in 2 ways, for example, as 18731584 + 993699529 = 4328^2 + 31523^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012431113 - 2² = 1012431109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012431091 and 1012431100.

It is not an unprimeable number, because it can be changed into a prime (1012431193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1596578 + ... + 1597211.

It is an arithmetic number, because the mean of its divisors is an integer number (253906305).

Almost surely, 2^1012431113 is an apocalyptic number.

It is an amenable number.

1012431113 is a deficient number, since it is larger than the sum of its proper divisors (3194107).

1012431113 is an equidigital number, since it uses as much as digits as its factorization.

1012431113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3194106.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1012431113 is about 31818.7226802083. The cubic root of 1012431113 is about 1004.1266516549.

Adding to 1012431113 its reverse (3111342101), we get a palindrome (4123773214).

The spelling of 1012431113 in words is "one billion, twelve million, four hundred thirty-one thousand, one hundred thirteen".