101248333 has 2 divisors, whose sum is σ = 101248334. Its totient is φ = 101248332.

The previous prime is 101248319. The next prime is 101248363. The reversal of 101248333 is 333842101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101243844 + 4489 = 10062^2 + 67^2 .

It is an emirp because it is prime and its reverse (333842101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101248333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101248298 and 101248307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101248363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50624166 + 50624167.

It is an arithmetic number, because the mean of its divisors is an integer number (50624167).

Almost surely, 2^101248333 is an apocalyptic number.

It is an amenable number.

101248333 is a deficient number, since it is larger than the sum of its proper divisors (1).

101248333 is an equidigital number, since it uses as much as digits as its factorization.

101248333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

The square root of 101248333 is about 10062.2230645121. The cubic root of 101248333 is about 466.0823179746.

The spelling of 101248333 in words is "one hundred one million, two hundred forty-eight thousand, three hundred thirty-three".