101300103131 has 2 divisors, whose sum is σ = 101300103132. Its totient is φ = 101300103130.

The previous prime is 101300103127. The next prime is 101300103133. The reversal of 101300103131 is 131301003101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101300103131 - 2² = 101300103127 is a prime.

It is a super-2 number, since 2×101300103131² (a number of 23 digits) contains 22 as substring.

Together with 101300103133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101300103133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650051565 + 50650051566.

It is an arithmetic number, because the mean of its divisors is an integer number (50650051566).

Almost surely, 2^101300103131 is an apocalyptic number.

101300103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101300103131 is an equidigital number, since it uses as much as digits as its factorization.

101300103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 101300103131 its reverse (131301003101), we get a palindrome (232601106232).

The spelling of 101300103131 in words is "one hundred one billion, three hundred million, one hundred three thousand, one hundred thirty-one".