Base | Representation |
---|---|
bin | 1001001101101001001111… |
… | …0101101101000111010111 |
3 | 1022212102100001000210110212 |
4 | 2103122103311231013113 |
5 | 2311432231340310033 |
6 | 33313355215240035 |
7 | 2063604112413035 |
oct | 223322365550727 |
9 | 38772301023425 |
10 | 10130013213143 |
11 | 32561294083aa |
12 | 1177320b1901b |
13 | 5863439a8285 |
14 | 27041c277555 |
15 | 128789016748 |
hex | 93693d6d1d7 |
10130013213143 has 2 divisors, whose sum is σ = 10130013213144. Its totient is φ = 10130013213142.
The previous prime is 10130013213071. The next prime is 10130013213161. The reversal of 10130013213143 is 34131231003101.
It is a strong prime.
It is an emirp because it is prime and its reverse (34131231003101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10130013213143 - 218 = 10130012950999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130313213143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065006606571 + 5065006606572.
It is an arithmetic number, because the mean of its divisors is an integer number (5065006606572).
Almost surely, 210130013213143 is an apocalyptic number.
10130013213143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130013213143 is an equidigital number, since it uses as much as digits as its factorization.
10130013213143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 10130013213143 its reverse (34131231003101), we get a palindrome (44261244216244).
The spelling of 10130013213143 in words is "ten trillion, one hundred thirty billion, thirteen million, two hundred thirteen thousand, one hundred forty-three".
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