Base | Representation |
---|---|
bin | 10010110111100101… |
… | …11100111101000101 |
3 | 222010222102020110012 |
4 | 21123302330331011 |
5 | 131221241034432 |
6 | 4353105240005 |
7 | 506013506342 |
oct | 113362747505 |
9 | 28128366405 |
10 | 10130018117 |
11 | 43291495aa |
12 | 1b68633005 |
13 | c5591127b |
14 | 6c15297c9 |
15 | 3e44e1cb2 |
hex | 25bcbcf45 |
10130018117 has 2 divisors, whose sum is σ = 10130018118. Its totient is φ = 10130018116.
The previous prime is 10130018071. The next prime is 10130018153. The reversal of 10130018117 is 71181003101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7533198436 + 2596819681 = 86794^2 + 50959^2 .
It is a cyclic number.
It is not a de Polignac number, because 10130018117 - 218 = 10129755973 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10130018092 and 10130018101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130011117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065009058 + 5065009059.
It is an arithmetic number, because the mean of its divisors is an integer number (5065009059).
Almost surely, 210130018117 is an apocalyptic number.
It is an amenable number.
10130018117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130018117 is an equidigital number, since it uses as much as digits as its factorization.
10130018117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 23.
The spelling of 10130018117 in words is "ten billion, one hundred thirty million, eighteen thousand, one hundred seventeen".
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