Search a number
-
+
10130035 = 54334679
BaseRepresentation
bin100110101001…
…001001110011
3201001122210111
4212221021303
510043130120
61001042151
7152050426
oct46511163
921048714
1010130035
115799933
123486357
132138b06
1414b99bd
15d5175a
hex9a9273

10130035 has 8 divisors (see below), whose sum is σ = 12186720. Its totient is φ = 8083584.

The previous prime is 10130033. The next prime is 10130039. The reversal of 10130035 is 53003101.

10130035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10130035 - 21 = 10130033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10129997 and 10130024.

It is not an unprimeable number, because it can be changed into a prime (10130033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175 + ... + 4504.

It is an arithmetic number, because the mean of its divisors is an integer number (1523340).

Almost surely, 210130035 is an apocalyptic number.

10130035 is a deficient number, since it is larger than the sum of its proper divisors (2056685).

10130035 is an equidigital number, since it uses as much as digits as its factorization.

10130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5117.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 10130035 is about 3182.7715909251. The cubic root of 10130035 is about 216.3732899817.

Adding to 10130035 its reverse (53003101), we get a palindrome (63133136).

The spelling of 10130035 in words is "ten million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 433 2165 4679 23395 2026007 10130035