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101302441410047 is a prime number
BaseRepresentation
bin10111000010001001010000…
…000010001111110111111111
3111021200102022022121110111012
4113002021100002033313333
5101234214400000110142
6555241411002145435
730223600635360323
oct2702112002176777
9437612268543435
10101302441410047
112a307140254919
12b4411127b227b
13446aa18c975c7
141b030c8719983
15baa197bea882
hex5c225008fdff

101302441410047 has 2 divisors, whose sum is σ = 101302441410048. Its totient is φ = 101302441410046.

The previous prime is 101302441410043. The next prime is 101302441410197. The reversal of 101302441410047 is 740014144203101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101302441410047 - 22 = 101302441410043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101302441409995 and 101302441410022.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101302441410043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50651220705023 + 50651220705024.

It is an arithmetic number, because the mean of its divisors is an integer number (50651220705024).

Almost surely, 2101302441410047 is an apocalyptic number.

101302441410047 is a deficient number, since it is larger than the sum of its proper divisors (1).

101302441410047 is an equidigital number, since it uses as much as digits as its factorization.

101302441410047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 32.

Adding to 101302441410047 its reverse (740014144203101), we get a palindrome (841316585613148).

The spelling of 101302441410047 in words is "one hundred one trillion, three hundred two billion, four hundred forty-one million, four hundred ten thousand, forty-seven".