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10130253149 is a prime number
BaseRepresentation
bin10010110111100111…
…10110010101011101
3222010222212011212002
421123303312111131
5131221321100044
64353114252045
7506015505512
oct113363662535
928128764762
1010130253149
11432929a145
121b68727025
13c55994243
146c158b309
153e453b74e
hex25bcf655d

10130253149 has 2 divisors, whose sum is σ = 10130253150. Its totient is φ = 10130253148.

The previous prime is 10130253127. The next prime is 10130253151. The reversal of 10130253149 is 94135203101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9681576025 + 448677124 = 98395^2 + 21182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10130253149 is a prime.

Together with 10130253151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10130253109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065126574 + 5065126575.

It is an arithmetic number, because the mean of its divisors is an integer number (5065126575).

Almost surely, 210130253149 is an apocalyptic number.

It is an amenable number.

10130253149 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130253149 is an equidigital number, since it uses as much as digits as its factorization.

10130253149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 29.

It can be divided in two parts, 101302 and 53149, that added together give a palindrome (154451).

The spelling of 10130253149 in words is "ten billion, one hundred thirty million, two hundred fifty-three thousand, one hundred forty-nine".