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1013041113142 = 2506520556571
BaseRepresentation
bin11101011110111011111…
…01001010100000110110
310120211211120120121120111
432233131331022200312
5113044202011110032
62053215030453234
7133122050246032
oct16573575124066
93524746517514
101013041113142
113606a0331253
1214440150421a
13746b6033936
14370624351c2
151b5415d9c47
hexebddf4a836

1013041113142 has 4 divisors (see below), whose sum is σ = 1519561669716. Its totient is φ = 506520556570.

The previous prime is 1013041113127. The next prime is 1013041113169. The reversal of 1013041113142 is 2413111403101.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×10130411131422 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253260278284 + ... + 253260278287.

It is an arithmetic number, because the mean of its divisors is an integer number (379890417429).

Almost surely, 21013041113142 is an apocalyptic number.

1013041113142 is a deficient number, since it is larger than the sum of its proper divisors (506520556574).

1013041113142 is an equidigital number, since it uses as much as digits as its factorization.

1013041113142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 506520556573.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1013041113142 its reverse (2413111403101), we get a palindrome (3426152516243).

The spelling of 1013041113142 in words is "one trillion, thirteen billion, forty-one million, one hundred thirteen thousand, one hundred forty-two".

Divisors: 1 2 506520556571 1013041113142