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1013043413551 = 1377926416427
BaseRepresentation
bin11101011110111100001…
…01111100001000101111
310120211211201220111010211
432233132011330020233
5113044203103213201
62053215152043251
7133122105636541
oct16573605741057
93524751814124
101013043413551
113606a1662614
12144402233527
13746b665aa20
1437062873691
151b5418e1651
hexebde17c22f

1013043413551 has 4 divisors (see below), whose sum is σ = 1090969829992. Its totient is φ = 935116997112.

The previous prime is 1013043413549. The next prime is 1013043413573. The reversal of 1013043413551 is 1553143403101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1013043413551 - 21 = 1013043413549 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1013043413531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38963208201 + ... + 38963208226.

It is an arithmetic number, because the mean of its divisors is an integer number (272742457498).

Almost surely, 21013043413551 is an apocalyptic number.

1013043413551 is a deficient number, since it is larger than the sum of its proper divisors (77926416441).

1013043413551 is an equidigital number, since it uses as much as digits as its factorization.

1013043413551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77926416440.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1013043413551 its reverse (1553143403101), we get a palindrome (2566186816652).

The spelling of 1013043413551 in words is "one trillion, thirteen billion, forty-three million, four hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 13 77926416427 1013043413551