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10131031021211 is a prime number
BaseRepresentation
bin1001001101101101000010…
…0000010101011010011011
31022212111221222012210122222
42103123100200111122123
52311441322420134321
633314044214334255
72063641251553352
oct223332040253233
938774858183588
1010131031021211
1132566009946a1
12117756595a38b
1358647680bc79
142704b74dc999
151287e85643ab
hex936d081569b

10131031021211 has 2 divisors, whose sum is σ = 10131031021212. Its totient is φ = 10131031021210.

The previous prime is 10131031021201. The next prime is 10131031021213. The reversal of 10131031021211 is 11212013013101.

It is a strong prime.

It is an emirp because it is prime and its reverse (11212013013101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10131031021211 - 218 = 10131030759067 is a prime.

Together with 10131031021213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10131031021211.

It is not a weakly prime, because it can be changed into another prime (10131031021213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065515510605 + 5065515510606.

It is an arithmetic number, because the mean of its divisors is an integer number (5065515510606).

Almost surely, 210131031021211 is an apocalyptic number.

10131031021211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131031021211 is an equidigital number, since it uses as much as digits as its factorization.

10131031021211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 10131031021211 its reverse (11212013013101), we get a palindrome (21343044034312).

The spelling of 10131031021211 in words is "ten trillion, one hundred thirty-one billion, thirty-one million, twenty-one thousand, two hundred eleven".