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10131050543 = 39725519019
BaseRepresentation
bin10010110111101101…
…11001000000101111
3222011001100200200012
421123312321000233
5131222022104133
64353143323435
7506025336335
oct113366710057
928131320605
1010131050543
114329794249
121b68a5057b
13c55bb3183
146c1717b55
153e4647b48
hex25bdb902f

10131050543 has 4 divisors (see below), whose sum is σ = 10156569960. Its totient is φ = 10105531128.

The previous prime is 10131050519. The next prime is 10131050551. The reversal of 10131050543 is 34505013101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10131050543 - 212 = 10131046447 is a prime.

It is a super-3 number, since 3×101310505433 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10131050243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12759113 + ... + 12759906.

It is an arithmetic number, because the mean of its divisors is an integer number (2539142490).

Almost surely, 210131050543 is an apocalyptic number.

10131050543 is a deficient number, since it is larger than the sum of its proper divisors (25519417).

10131050543 is an equidigital number, since it uses as much as digits as its factorization.

10131050543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25519416.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 10131050543 its reverse (34505013101), we get a palindrome (44636063644).

The spelling of 10131050543 in words is "ten billion, one hundred thirty-one million, fifty thousand, five hundred forty-three".

Divisors: 1 397 25519019 10131050543