1013111503 has 2 divisors, whose sum is σ = 1013111504. Its totient is φ = 1013111502.

The previous prime is 1013111501. The next prime is 1013111513. The reversal of 1013111503 is 3051113101.

It is a weak prime.

It is an emirp because it is prime and its reverse (3051113101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1013111503 - 2¹ = 1013111501 is a prime.

Together with 1013111501, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013111501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506555751 + 506555752.

It is an arithmetic number, because the mean of its divisors is an integer number (506555752).

Almost surely, 2^1013111503 is an apocalyptic number.

1013111503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013111503 is an equidigital number, since it uses as much as digits as its factorization.

1013111503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 16.

The square root of 1013111503 is about 31829.4125456314. The cubic root of 1013111503 is about 1004.3515376533.

Adding to 1013111503 its reverse (3051113101), we get a palindrome (4064224604).

The spelling of 1013111503 in words is "one billion, thirteen million, one hundred eleven thousand, five hundred three".