1013113014311 has 2 divisors, whose sum is σ = 1013113014312. Its totient is φ = 1013113014310.

The previous prime is 1013113014289. The next prime is 1013113014313. The reversal of 1013113014311 is 1134103113101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013113014311 is a prime.

It is a super-3 number, since 3×1013113014311³ (a number of 37 digits) contains 333 as substring.

Together with 1013113014313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013113014313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506556507155 + 506556507156.

It is an arithmetic number, because the mean of its divisors is an integer number (506556507156).

Almost surely, 2^{1013113014311} is an apocalyptic number.

1013113014311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013113014311 is an equidigital number, since it uses as much as digits as its factorization.

1013113014311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1013113014311 its reverse (1134103113101), we get a palindrome (2147216127412).

The spelling of 1013113014311 in words is "one trillion, thirteen billion, one hundred thirteen million, fourteen thousand, three hundred eleven".