Base | Representation |
---|---|
bin | 1100000100111… |
… | …10011101100001 |
3 | 21001122012102101 |
4 | 12002132131201 |
5 | 201413443403 |
6 | 14015250401 |
7 | 2340066202 |
oct | 602363541 |
9 | 231565371 |
10 | 101312353 |
11 | 5220851a |
12 | 29b19a01 |
13 | 17cb2c4c |
14 | d6535a9 |
15 | 8d6371d |
hex | 609e761 |
101312353 has 4 divisors (see below), whose sum is σ = 103783428. Its totient is φ = 98841280.
The previous prime is 101312317. The next prime is 101312383. The reversal of 101312353 is 353213101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 353213101 = 31 ⋅11393971.
It can be written as a sum of positive squares in 2 ways, for example, as 35247969 + 66064384 = 5937^2 + 8128^2 .
It is a cyclic number.
It is not a de Polignac number, because 101312353 - 29 = 101311841 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 101312353.
It is not an unprimeable number, because it can be changed into a prime (101312383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1235476 + ... + 1235557.
It is an arithmetic number, because the mean of its divisors is an integer number (25945857).
Almost surely, 2101312353 is an apocalyptic number.
It is an amenable number.
101312353 is a deficient number, since it is larger than the sum of its proper divisors (2471075).
101312353 is an equidigital number, since it uses as much as digits as its factorization.
101312353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2471074.
The product of its (nonzero) digits is 270, while the sum is 19.
The square root of 101312353 is about 10065.4037673608. The cubic root of 101312353 is about 466.1805329353.
Adding to 101312353 its reverse (353213101), we get a palindrome (454525454).
It can be divided in two parts, 1013123 and 53, that added together give a triangular number (1013176 = T1423).
The spelling of 101312353 in words is "one hundred one million, three hundred twelve thousand, three hundred fifty-three".
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