Base | Representation |
---|---|
bin | 1001001101101110000111… |
… | …1010111101000101010101 |
3 | 1022212112201100000122020101 |
4 | 2103123201322331011111 |
5 | 2311442422220241432 |
6 | 33314133213134101 |
7 | 2063651430260032 |
oct | 223334172750525 |
9 | 38775640018211 |
10 | 10131323212117 |
11 | 3256740914a88 |
12 | 117762778a331 |
13 | 5864c22044b3 |
14 | 27050423c389 |
15 | 12881402e4e7 |
hex | 936e1ebd155 |
10131323212117 has 2 divisors, whose sum is σ = 10131323212118. Its totient is φ = 10131323212116.
The previous prime is 10131323212097. The next prime is 10131323212169. The reversal of 10131323212117 is 71121232313101.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7884364183921 + 2246959028196 = 2807911^2 + 1498986^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10131323212117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10131323210117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065661606058 + 5065661606059.
It is an arithmetic number, because the mean of its divisors is an integer number (5065661606059).
Almost surely, 210131323212117 is an apocalyptic number.
It is an amenable number.
10131323212117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131323212117 is an equidigital number, since it uses as much as digits as its factorization.
10131323212117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 10131323212117 its reverse (71121232313101), we get a palindrome (81252555525218).
The spelling of 10131323212117 in words is "ten trillion, one hundred thirty-one billion, three hundred twenty-three million, two hundred twelve thousand, one hundred seventeen".
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