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10131432011 is a prime number
BaseRepresentation
bin10010110111110000…
…10110001001001011
3222011002002001221122
421123320112021023
5131222121311021
64353155425455
7506031515441
oct113370261113
928132061848
1010131432011
114329a24908
121b68bb528b
13c55cb79ac
146c17b6b91
153e46c0bab
hex25be1624b

10131432011 has 2 divisors, whose sum is σ = 10131432012. Its totient is φ = 10131432010.

The previous prime is 10131431983. The next prime is 10131432023. The reversal of 10131432011 is 11023413101.

10131432011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10131432011 is a prime.

It is a super-3 number, since 3×101314320113 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10131432071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065716005 + 5065716006.

It is an arithmetic number, because the mean of its divisors is an integer number (5065716006).

Almost surely, 210131432011 is an apocalyptic number.

10131432011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131432011 is an equidigital number, since it uses as much as digits as its factorization.

10131432011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10131432011 its reverse (11023413101), we get a palindrome (21154845112).

The spelling of 10131432011 in words is "ten billion, one hundred thirty-one million, four hundred thirty-two thousand, eleven".