10132103100113 has 4 divisors (see below), whose sum is σ = 10176737915760. Its totient is φ = 10087468284468.

The previous prime is 10132103100071. The next prime is 10132103100209. The reversal of 10132103100113 is 31100130123101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10132103100113 - 2³⁸ = 9857225193169 is a prime.

It is a super-2 number, since 2×10132103100113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10132103100091 and 10132103100100.

It is not an unprimeable number, because it can be changed into a prime (10132103106113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22317407483 + ... + 22317407936.

It is an arithmetic number, because the mean of its divisors is an integer number (2544184478940).

Almost surely, 2^{10132103100113} is an apocalyptic number.

It is an amenable number.

10132103100113 is a deficient number, since it is larger than the sum of its proper divisors (44634815647).

10132103100113 is an equidigital number, since it uses as much as digits as its factorization.

10132103100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44634815646.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10132103100113 its reverse (31100130123101), we get a palindrome (41232233223214).

The spelling of 10132103100113 in words is "ten trillion, one hundred thirty-two billion, one hundred three million, one hundred thousand, one hundred thirteen".