10132113301 has 4 divisors (see below), whose sum is σ = 10143588832. Its totient is φ = 10120637772.

The previous prime is 10132113287. The next prime is 10132113319. The reversal of 10132113301 is 10331123101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10331123101 = 13 ⋅794701777.

It is a cyclic number.

It is not a de Polignac number, because 10132113301 - 2⁵ = 10132113269 is a prime.

It is a super-2 number, since 2×10132113301² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10132113001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5736441 + ... + 5738206.

It is an arithmetic number, because the mean of its divisors is an integer number (2535897208).

Almost surely, 2^10132113301 is an apocalyptic number.

It is an amenable number.

10132113301 is a deficient number, since it is larger than the sum of its proper divisors (11475531).

10132113301 is an equidigital number, since it uses as much as digits as its factorization.

10132113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11475530.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10132113301 its reverse (10331123101), we get a palindrome (20463236402).

The spelling of 10132113301 in words is "ten billion, one hundred thirty-two million, one hundred thirteen thousand, three hundred one".