Base | Representation |
---|---|
bin | 10111000010011010101110… |
… | …110110110101100001000111 |
3 | 111021202012202111000111012201 |
4 | 113002122232312311201013 |
5 | 101240021320300420312 |
6 | 555254153335455331 |
7 | 30225134042660506 |
oct | 2702325666654107 |
9 | 437665674014181 |
10 | 101321212123207 |
11 | 2a3140a28944aa |
12 | b444890b27547 |
13 | 446c71aa9557b |
14 | 1b03d8964a83d |
15 | baa8e5a93557 |
hex | 5c26aedb5847 |
101321212123207 has 2 divisors, whose sum is σ = 101321212123208. Its totient is φ = 101321212123206.
The previous prime is 101321212123193. The next prime is 101321212123249. The reversal of 101321212123207 is 702321212123101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101321212123207 is a prime.
It is a super-2 number, since 2×1013212121232072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101321212123267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660606061603 + 50660606061604.
It is an arithmetic number, because the mean of its divisors is an integer number (50660606061604).
Almost surely, 2101321212123207 is an apocalyptic number.
101321212123207 is a deficient number, since it is larger than the sum of its proper divisors (1).
101321212123207 is an equidigital number, since it uses as much as digits as its factorization.
101321212123207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 101321212123207 its reverse (702321212123101), we get a palindrome (803642424246308).
The spelling of 101321212123207 in words is "one hundred one trillion, three hundred twenty-one billion, two hundred twelve million, one hundred twenty-three thousand, two hundred seven".
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