10132122113 has 2 divisors, whose sum is σ = 10132122114. Its totient is φ = 10132122112.

The previous prime is 10132122041. The next prime is 10132122137. The reversal of 10132122113 is 31122123101.

10132122113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9961636864 + 170485249 = 99808^2 + 13057^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10132122113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10132122091 and 10132122100.

It is not a weakly prime, because it can be changed into another prime (10132122193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066061056 + 5066061057.

It is an arithmetic number, because the mean of its divisors is an integer number (5066061057).

Almost surely, 2^10132122113 is an apocalyptic number.

It is an amenable number.

10132122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10132122113 is an equidigital number, since it uses as much as digits as its factorization.

10132122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10132122113 its reverse (31122123101), we get a palindrome (41254245214).

The spelling of 10132122113 in words is "ten billion, one hundred thirty-two million, one hundred twenty-two thousand, one hundred thirteen".