101330113 has 2 divisors, whose sum is σ = 101330114. Its totient is φ = 101330112.

The previous prime is 101330107. The next prime is 101330123. The reversal of 101330113 is 311033101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64448784 + 36881329 = 8028^2 + 6073^2 .

It is an emirp because it is prime and its reverse (311033101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101330113 - 2¹⁷ = 101199041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101330093 and 101330102.

It is not a weakly prime, because it can be changed into another prime (101330123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50665056 + 50665057.

It is an arithmetic number, because the mean of its divisors is an integer number (50665057).

Almost surely, 2^101330113 is an apocalyptic number.

It is an amenable number.

101330113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101330113 is an equidigital number, since it uses as much as digits as its factorization.

101330113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 13.

The square root of 101330113 is about 10066.2859585847. The cubic root of 101330113 is about 466.2077717411.

Adding to 101330113 its reverse (311033101), we get a palindrome (412363214).

The spelling of 101330113 in words is "one hundred one million, three hundred thirty thousand, one hundred thirteen".