10133040113 has 16 divisors (see below), whose sum is σ = 12136348800. Its totient is φ = 8450710128.

The previous prime is 10133040109. The next prime is 10133040163. The reversal of 10133040113 is 31104033101.

It is not a de Polignac number, because 10133040113 - 2² = 10133040109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10133040091 and 10133040100.

It is not an unprimeable number, because it can be changed into a prime (10133040163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 386531 + ... + 411912.

It is an arithmetic number, because the mean of its divisors is an integer number (758521800).

Almost surely, 2^10133040113 is an apocalyptic number.

It is an amenable number.

10133040113 is a deficient number, since it is larger than the sum of its proper divisors (2003308687).

10133040113 is an frugal number, since it uses more digits than its factorization.

10133040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 798501 (or 798487 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10133040113 its reverse (31104033101), we get a palindrome (41237073214).

The spelling of 10133040113 in words is "ten billion, one hundred thirty-three million, forty thousand, one hundred thirteen".