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101331064022437 is a prime number
BaseRepresentation
bin10111000010100011111010…
…000100110110010110100101
3111021210011012002002211021101
4113002203322010312112211
5101240202004342204222
6555302503112120101
730225633141513004
oct2702437204662645
9437704162084241
10101331064022437
112a318298a44187
12b446780396031
13447062ab9a442
141b04641c5ac3b
15baacc0949927
hex5c28fa1365a5

101331064022437 has 2 divisors, whose sum is σ = 101331064022438. Its totient is φ = 101331064022436.

The previous prime is 101331064022393. The next prime is 101331064022453. The reversal of 101331064022437 is 734220460133101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97249556987361 + 4081507035076 = 9861519^2 + 2020274^2 .

It is a cyclic number.

It is not a de Polignac number, because 101331064022437 - 239 = 100781308208549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101331064022396 and 101331064022405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101331064022477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50665532011218 + 50665532011219.

It is an arithmetic number, because the mean of its divisors is an integer number (50665532011219).

Almost surely, 2101331064022437 is an apocalyptic number.

It is an amenable number.

101331064022437 is a deficient number, since it is larger than the sum of its proper divisors (1).

101331064022437 is an equidigital number, since it uses as much as digits as its factorization.

101331064022437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 37.

The spelling of 101331064022437 in words is "one hundred one trillion, three hundred thirty-one billion, sixty-four million, twenty-two thousand, four hundred thirty-seven".