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10133223012119 is a prime number
BaseRepresentation
bin1001001101110101001100…
…1010000111011100010111
31022212201121201211110220102
42103131103022013130113
52312010320042341434
633315045520324315
72064046466304404
oct223352312073427
938781551743812
1010133223012119
113257526243929
121177a77a7369b
13586735997ccc
142706446932ab
151288c5bed07e
hex93753287717

10133223012119 has 2 divisors, whose sum is σ = 10133223012120. Its totient is φ = 10133223012118.

The previous prime is 10133223012097. The next prime is 10133223012149. The reversal of 10133223012119 is 91121032233101.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10133223012119 is a prime.

It is a super-2 number, since 2×101332230121192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10133223012091 and 10133223012100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10133223012149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066611506059 + 5066611506060.

It is an arithmetic number, because the mean of its divisors is an integer number (5066611506060).

Almost surely, 210133223012119 is an apocalyptic number.

10133223012119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10133223012119 is an equidigital number, since it uses as much as digits as its factorization.

10133223012119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 10133223012119 in words is "ten trillion, one hundred thirty-three billion, two hundred twenty-three million, twelve thousand, one hundred nineteen".