Base | Representation |
---|---|
bin | 10010110111111111… |
… | …00011000111000010 |
3 | 222011012121222221222 |
4 | 21123333203013002 |
5 | 131223112221010 |
6 | 4353304115042 |
7 | 506053541243 |
oct | 113377430702 |
9 | 28135558858 |
10 | 10133320130 |
11 | 432aaa443a |
12 | 1b69765a82 |
13 | c564c921b |
14 | 6c1b48cca |
15 | 3e4945355 |
hex | 25bfe31c2 |
10133320130 has 8 divisors (see below), whose sum is σ = 18239976252. Its totient is φ = 4053328048.
The previous prime is 10133320111. The next prime is 10133320139. The reversal of 10133320130 is 3102333101.
It can be written as a sum of positive squares in 2 ways, for example, as 9299323489 + 833996641 = 96433^2 + 28879^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 10133320099 and 10133320108.
It is not an unprimeable number, because it can be changed into a prime (10133320139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 506665997 + ... + 506666016.
Almost surely, 210133320130 is an apocalyptic number.
10133320130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10133320130 is a deficient number, since it is larger than the sum of its proper divisors (8106656122).
10133320130 is a wasteful number, since it uses less digits than its factorization.
10133320130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1013332020.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 10133320130 its reverse (3102333101), we get a palindrome (13235653231).
The spelling of 10133320130 in words is "ten billion, one hundred thirty-three million, three hundred twenty thousand, one hundred thirty".
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