1013391941 has 2 divisors, whose sum is σ = 1013391942. Its totient is φ = 1013391940.

The previous prime is 1013391931. The next prime is 1013391943. The reversal of 1013391941 is 1491933101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 992880100 + 20511841 = 31510^2 + 4529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013391941 is a prime.

It is a Sophie Germain prime.

Together with 1013391943, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1013391898 and 1013391907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013391943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506695970 + 506695971.

It is an arithmetic number, because the mean of its divisors is an integer number (506695971).

Almost surely, 2^1013391941 is an apocalyptic number.

It is an amenable number.

1013391941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013391941 is an equidigital number, since it uses as much as digits as its factorization.

1013391941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 32.

The square root of 1013391941 is about 31833.8175687428. The cubic root of 1013391941 is about 1004.4442001593. Note that the first 3 decimals are identical.

The spelling of 1013391941 in words is "one billion, thirteen million, three hundred ninety-one thousand, nine hundred forty-one".