Base | Representation |
---|---|
bin | 11101011111100110111… |
… | …11011110101100011111 |
3 | 10120212202202110102110012 |
4 | 32233303133132230133 |
5 | 113100422010231424 |
6 | 2053314535033435 |
7 | 133134025346453 |
oct | 16576337365437 |
9 | 3525682412405 |
10 | 1013402430239 |
11 | 360866286121 |
12 | 1444a250b87b |
13 | 74742b50034 |
14 | 3709840a663 |
15 | 1b5631abb0e |
hex | ebf37deb1f |
1013402430239 has 2 divisors, whose sum is σ = 1013402430240. Its totient is φ = 1013402430238.
The previous prime is 1013402430197. The next prime is 1013402430241. The reversal of 1013402430239 is 9320342043101.
It is a strong prime.
It is an emirp because it is prime and its reverse (9320342043101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1013402430239 - 28 = 1013402429983 is a prime.
It is a super-2 number, since 2×10134024302392 (a number of 25 digits) contains 22 as substring.
Together with 1013402430241, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1013402630239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506701215119 + 506701215120.
It is an arithmetic number, because the mean of its divisors is an integer number (506701215120).
Almost surely, 21013402430239 is an apocalyptic number.
1013402430239 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013402430239 is an equidigital number, since it uses as much as digits as its factorization.
1013402430239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 1013402430239 in words is "one trillion, thirteen billion, four hundred two million, four hundred thirty thousand, two hundred thirty-nine".
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