1013442432133 has 4 divisors (see below), whose sum is σ = 1035005037120. Its totient is φ = 991879827148.

The previous prime is 1013442432113. The next prime is 1013442432137. The reversal of 1013442432133 is 3312342443101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013442432133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1013442432095 and 1013442432104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1013442432137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10781302423 + ... + 10781302516.

It is an arithmetic number, because the mean of its divisors is an integer number (258751259280).

Almost surely, 2^{1013442432133} is an apocalyptic number.

It is an amenable number.

1013442432133 is a deficient number, since it is larger than the sum of its proper divisors (21562604987).

1013442432133 is an equidigital number, since it uses as much as digits as its factorization.

1013442432133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21562604986.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1013442432133 its reverse (3312342443101), we get a palindrome (4325784875234).

The spelling of 1013442432133 in words is "one trillion, thirteen billion, four hundred forty-two million, four hundred thirty-two thousand, one hundred thirty-three".