10140044000131 has 2 divisors, whose sum is σ = 10140044000132. Its totient is φ = 10140044000130.

The previous prime is 10140044000129. The next prime is 10140044000237. The reversal of 10140044000131 is 13100044004101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10140044000131 - 2¹ = 10140044000129 is a prime.

It is a super-2 number, since 2×10140044000131² (a number of 27 digits) contains 22 as substring.

Together with 10140044000129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10140044000099 and 10140044000108.

It is not a weakly prime, because it can be changed into another prime (10140044000101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5070022000065 + 5070022000066.

It is an arithmetic number, because the mean of its divisors is an integer number (5070022000066).

Almost surely, 2^{10140044000131} is an apocalyptic number.

10140044000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10140044000131 is an equidigital number, since it uses as much as digits as its factorization.

10140044000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 10140044000131 its reverse (13100044004101), we get a palindrome (23240088004232).

The spelling of 10140044000131 in words is "ten trillion, one hundred forty billion, forty-four million, one hundred thirty-one", and thus it is an aban number.