101401131401 has 4 divisors (see below), whose sum is σ = 101404182804. Its totient is φ = 101398080000.

The previous prime is 101401131397. The next prime is 101401131413. The reversal of 101401131401 is 104131104101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4741699600 + 96659431801 = 68860^2 + 310901^2 .

It is a cyclic number.

It is not a de Polignac number, because 101401131401 - 2² = 101401131397 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101401131401.

It is not an unprimeable number, because it can be changed into a prime (101401137401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1475300 + ... + 1542501.

It is an arithmetic number, because the mean of its divisors is an integer number (25351045701).

Almost surely, 2^101401131401 is an apocalyptic number.

It is an amenable number.

101401131401 is a deficient number, since it is larger than the sum of its proper divisors (3051403).

101401131401 is an equidigital number, since it uses as much as digits as its factorization.

101401131401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3051402.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101401131401 its reverse (104131104101), we get a palindrome (205532235502).

The spelling of 101401131401 in words is "one hundred one billion, four hundred one million, one hundred thirty-one thousand, four hundred one".